14z^2+27z-2=0

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Solution for 14z^2+27z-2=0 equation:



14z^2+27z-2=0
a = 14; b = 27; c = -2;
Δ = b2-4ac
Δ = 272-4·14·(-2)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-29}{2*14}=\frac{-56}{28} =-2 $
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+29}{2*14}=\frac{2}{28} =1/14 $

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